Sortarea este o modalitate de a aranja elementele unei liste sau ale unei matrice într-o anumită ordine. Ordinea poate fi în ordine crescătoare sau descrescătoare. The numeric și lexicografic Ordinea (alfabetică) este o ordine larg utilizată.
În această secțiune, vom învăța cum se sortează matricea în Java în ascendent și Descendentă comanda folosind fel() metoda si fără a utiliza metoda sort(). . Odată cu asta vom învăța și noi cum se sortează subbary în Java .
Java șir înlocuiește toate
Sortați matricea în ordine crescătoare
The ordine crescătoare aranjează elementele în ordinea cea mai mică la cea mai mare. Este cunoscut și ca ordinea naturală sau ordine numerică . Putem efectua sortarea în următoarele moduri:
- Folosind metoda sort().
- Fără a folosi metoda
- Folosind bucla for
- Folosind metoda definită de utilizator
Folosind metoda sort().
În Java, Matrice este clasa definită înjava.utilpachet care oferă fel() metodă de a sorta o matrice în ordine crescătoare. Folosește Algoritm dual-pivot Quicksort pentru sortare. Complexitatea sa este O(n log(n)) . Este un static metodă care analizează an matrice ca parametru și nu returnează nimic. Îl putem invoca direct folosind numele clasei. Acceptă o matrice de tip int, float, double, long, char, byte.
Sintaxă:
public static void sort(int[] a)
Unde A este o matrice care să fie scurtă.
Notă: Ca și clasa Arrays, clasa Collections oferă și metoda sort() pentru sortarea matricei. Dar există o diferență între ele. Metoda sort() a clasei Arrays funcționează pentru tipul primitiv, în timp ce metoda sort() a clasei Collections funcționează pentru obiecte Colecții, cum ar fi LinkedList, ArrayList etc.
Să sortăm o matrice folosind metoda sort() a clasei Arrays.
În programul următor, am definit o matrice de tip întreg. După aceea, am invocat metoda sort() a clasei Arrays și analizăm tabloul pentru a fi sortat. Pentru tipărirea matricei sortate, am folosit bucla for.
SortArrayExample1.java
import java.util.Arrays; public class SortArrayExample1 { public static void main(String[] args) { //defining an array of integer type int [] array = new int [] {90, 23, 5, 109, 12, 22, 67, 34}; //invoking sort() method of the Arrays class Arrays.sort(array); System.out.println('Elements of array sorted in ascending order: '); //prints array using the for loop for (int i = 0; i <array.length; i++) { system.out.println(array[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Array elements in ascending order: 5 12 22 23 34 67 90 109 </pre> <p>In the above program, we can also use the toSting() method of the Arrays class to print the array, as shown in the following statement. It returns a string representation of the specified array.</p> <pre> System.out.printf(Arrays.toString(array)); </pre> <h3>Without Using the Method</h3> <h3>Using the for Loop</h3> <p>In the following example, we have initialized an array of integer type and sort the array in ascending order.</p> <p> <strong>SortArrayExample2.java</strong> </p> <pre> public class SortArrayExample2 { public static void main(String[] args) { //creating an instance of an array int[] arr = new int[] {78, 34, 1, 3, 90, 34, -1, -4, 6, 55, 20, -65}; System.out.println('Array elements after sorting:'); //sorting logic for (int i = 0; i <arr.length; i++) { for (int j="i" + 1; arr[j]) tmp="arr[i];" arr[i]="arr[j];" arr[j]="tmp;" } prints the sorted element of array system.out.println(arr[i]); < pre> <p> <strong>Output:</strong> </p> <pre> Array elements after sorting: -65 -4 -1 1 3 6 20 34 34 55 78 90 </pre> <h3>Using the User Defined Method</h3> <p>In the following example, we have defined a method named <strong>sortArray()</strong> that contains the logic to sort an array in natural order.</p> <p> <strong>SortArrayExample3.java</strong> </p> <pre> public class SortArrayExample3 { public static void main(String[] args) { int i; //initializing an array int array[] = {12, 45, 1, -1, 0, 4, 56, 23, 89, -21, 56, 27}; System.out.print('Array elements before sorting:
'); for(i = 0; i <array.length; i++) system.out.println(array[i]); invoking user defined method sortarray(array, array.length); system.out.print('array elements after sorting:
'); accessing of the sorted array for(i="0;" i <array.length; { } to sort an in ascending order private static void sortarray(int array[], int n) for (int <n; j="i;" a="array[i];" while ((j> 0) && (array[j-1] > a)) //returns true when both conditions are true { array[j] = array[j-1]; j--; } array[j] = a; } } } </array.length;></pre> <p> <strong>Output:</strong> </p> <pre> Array elements before sorting: 12 45 1 -1 0 4 56 23 89 -21 56 27 Array elements after sorting: -21 -1 0 1 4 12 23 27 45 56 56 89 </pre> <h2>Sort Array in Descending Order</h2> <p>The <strong>descending order</strong> arranges the elements in the highest to lowest order. We can perform sorting in the following ways:</p> <ul> <li>Using the <strong>reverseOrder()</strong> Method</li> <li>Without using the method <ul> <li>Using the <strong>for</strong> Loop</li> <li>Using the <strong>User Defined</strong> Method</li> </ul></li> </ul> <h3>Using the reverseOrder() Method</h3> <p> <a href="/java-collections-class">Java <strong>Collections</strong> class</a> provides the <strong>reverseOrder()</strong> method to sort the array in reverse-lexicographic order. It is a static method, so we can invoke it directly by using the class name. It does not parse any parameter. It returns a <strong>comparator</strong> that imposes the reverse of the natural ordering (ascending order).</p> <p>It means that the array sorts elements in the ascending order by using the sort() method, after that the reverseOrder() method reverses the natural ordering, and we get the sorted array in descending order.</p> <p> <strong>Syntax:</strong> </p> <pre> public static Comparator reverseOrder() </pre> <p>Suppose, a[] is an array to be sort in the descending order. We will use the reverseOrder() method in the following way:</p> <pre> Arrays.sort(a, Collections.reverseOrder()); </pre> <p>Let's sorts an array in the descending order.</p> <p>In the following program, a point to be noticed that we have defined an array as <strong>Integer</strong> . Because the reverseOrder() method does not work for the primitive data type.</p> <p> <strong>SortArrayExample4.java</strong> </p> <pre> import java.util.Arrays; import java.util.Collections; public class SortArrayExample4 { public static void main(String[] args) { Integer [] array = {23, -9, 78, 102, 4, 0, -1, 11, 6, 110, 205}; // sorts array[] in descending order Arrays.sort(array, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(array)); } } </pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: [205, 110, 102, 78, 23, 11, 6, 4, 0, -1, -9] </pre> <p>Let's see another program that sorts array elements in alphabetical order.</p> <p> <strong>SortArrayExample5.java</strong> </p> <pre> import java.util.Arrays; import java.util.Collections; public class SortArrayExample5 { public static void main(String[] args) { String [] strarray = {'Mango', 'Apple', 'Grapes', 'Papaya', 'Pineapple', 'Banana', 'Orange'}; // sorts array[] in descending order Arrays.sort(strarray, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(strarray)); } } </pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: [Papaya, Pineapple, Orange, Mango, Grapes, Banana, Apple] </pre> <h3>Without Using the Method</h3> <h3>Using the for Loop</h3> <p>In the following example, we have initialized an integer array and perform sorting in descending order.</p> <p> <strong>SortArrayExample6.java</strong> </p> <pre> public class SortArrayExample6 { public static void main(String[] args) { int temp; //initializing an array int a[]={12,5,56,-2,32,2,-26,9,43,94,-78}; for (int i = 0; i <a.length; i++) { for (int j="i" + 1; < a.length; j++) if (a[i] a[j]) temp="a[i];" a[i]="a[j];" a[j]="temp;" } system.out.println('array elements in descending order:'); accessing element of the array i="0;" - system.out.println(a[i]); pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: 94 56 43 32 12 9 5 2 -2 -26 -78 </pre> <h3>Using the User Defined Method</h3> <p> <strong>SortArrayExample7.java</strong> </p> <pre> import java.util.Scanner; public class SortArrayExample7 { public static void main(String[] args) { int n, temp; Scanner s = new Scanner(System.in); System.out.print('Enter the number of elements: '); n = s.nextInt(); int a[] = new int[n]; System.out.println('Enter the elements of the array: '); for (int i = 0; i <n; i++) { a[i]="s.nextInt();" } for (int i="0;" < n; j="i" + 1; j++) if (a[i] a[j]) temp="a[i];" a[j]="temp;" system.out.println('array elements in descending order:'); n - system.out.println(a[i]); system.out.print(a[n 1]); pre> <p> <strong>Output:</strong> </p> <pre> Enter the number of elements: 7 Enter the elements of the array: 12 5 56 -2 32 2 -26 Array elements in descending order: 56 32 12 5 2 -2 -26 </pre> <h2>How to Sort Subarray</h2> <p>An array derived from the array is known as <strong>subarray</strong> . Suppose, <strong>a[]</strong> is an array having the elements [12, 90, 34, 2, 45, 3, 22, 18, 5, 78] and we want to sort array elements from 34 to 18. It will sort the subarray <strong>[34, 2, 45, 3, 22, 18]</strong> and keep the other elements as it is.</p> <p>To sort the subarray, the Arrays class provides the static method named <strong>sort()</strong> . It sorts the specified range of the array into ascending order. We can also sort the array of type <strong>long, double, float, char, byte,</strong> etc.</p> <p> <strong>Syntax:</strong> </p> <pre> public static void sort(int[] a, int fromIndex, int toIndex) </pre> <p>The method parses the following three parameters:</p> <ul> <tr><td>a:</td> An array to be sort. </tr><tr><td>fromIndex:</td> The index of the first element of the subarray. It participates in the sorting. </tr><tr><td>toIndex:</td> The index of the last element of the subarray. It does not participate in the sorting. </tr></ul> <p>If formIndex is equal to the toIndex, the range to be sorted is empty. It throws IllegalArgumentException if <strong>fomIndex is greater than toIndex</strong> . It also throws ArrayIndexOutOfBoundsException if <strong>fromIndex a.length</strong> .</p> <p>Let's sort a subarray through a Java program.</p> <p> <strong>SortSubarrayExample.java</strong> </p> <pre> import java.util.Arrays; public class SortSubarrayExample { public static void main(String[] args) { //defining an array int[] a = {12, 90, 34, 2, 45, 3, 22, 18, 5, 78}; // sorts subarray form index 2 to 7 Arrays.sort(a, 2, 7); //prints array using the for loop for (int i = 0; i <a.length; i++) { system.out.println(a[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Sorted Subarray: 12 90 2 3 22 34 45 18 5 78 </pre> <hr></a.length;></pre></n;></pre></a.length;></pre></arr.length;></pre></array.length;> În programul de mai sus, putem folosi și metoda toSting() a clasei Arrays pentru a imprima matricea, așa cum se arată în instrucțiunea următoare. Returnează o reprezentare șir a matricei specificate.
System.out.printf(Arrays.toString(array));
Fără a folosi metoda
Folosind bucla for
În exemplul următor, am inițializat o matrice de tip întreg și am sortat matricea în ordine crescătoare.
SortArrayExample2.java
public class SortArrayExample2 { public static void main(String[] args) { //creating an instance of an array int[] arr = new int[] {78, 34, 1, 3, 90, 34, -1, -4, 6, 55, 20, -65}; System.out.println('Array elements after sorting:'); //sorting logic for (int i = 0; i <arr.length; i++) { for (int j="i" + 1; arr[j]) tmp="arr[i];" arr[i]="arr[j];" arr[j]="tmp;" } prints the sorted element of array system.out.println(arr[i]); < pre> <p> <strong>Output:</strong> </p> <pre> Array elements after sorting: -65 -4 -1 1 3 6 20 34 34 55 78 90 </pre> <h3>Using the User Defined Method</h3> <p>In the following example, we have defined a method named <strong>sortArray()</strong> that contains the logic to sort an array in natural order.</p> <p> <strong>SortArrayExample3.java</strong> </p> <pre> public class SortArrayExample3 { public static void main(String[] args) { int i; //initializing an array int array[] = {12, 45, 1, -1, 0, 4, 56, 23, 89, -21, 56, 27}; System.out.print('Array elements before sorting:
'); for(i = 0; i <array.length; i++) system.out.println(array[i]); invoking user defined method sortarray(array, array.length); system.out.print(\'array elements after sorting:
\'); accessing of the sorted array for(i="0;" i <array.length; { } to sort an in ascending order private static void sortarray(int array[], int n) for (int <n; j="i;" a="array[i];" while ((j> 0) && (array[j-1] > a)) //returns true when both conditions are true { array[j] = array[j-1]; j--; } array[j] = a; } } } </array.length;></pre> <p> <strong>Output:</strong> </p> <pre> Array elements before sorting: 12 45 1 -1 0 4 56 23 89 -21 56 27 Array elements after sorting: -21 -1 0 1 4 12 23 27 45 56 56 89 </pre> <h2>Sort Array in Descending Order</h2> <p>The <strong>descending order</strong> arranges the elements in the highest to lowest order. We can perform sorting in the following ways:</p> <ul> <li>Using the <strong>reverseOrder()</strong> Method</li> <li>Without using the method <ul> <li>Using the <strong>for</strong> Loop</li> <li>Using the <strong>User Defined</strong> Method</li> </ul></li> </ul> <h3>Using the reverseOrder() Method</h3> <p> <a href="/java-collections-class">Java <strong>Collections</strong> class</a> provides the <strong>reverseOrder()</strong> method to sort the array in reverse-lexicographic order. It is a static method, so we can invoke it directly by using the class name. It does not parse any parameter. It returns a <strong>comparator</strong> that imposes the reverse of the natural ordering (ascending order).</p> <p>It means that the array sorts elements in the ascending order by using the sort() method, after that the reverseOrder() method reverses the natural ordering, and we get the sorted array in descending order.</p> <p> <strong>Syntax:</strong> </p> <pre> public static Comparator reverseOrder() </pre> <p>Suppose, a[] is an array to be sort in the descending order. We will use the reverseOrder() method in the following way:</p> <pre> Arrays.sort(a, Collections.reverseOrder()); </pre> <p>Let's sorts an array in the descending order.</p> <p>In the following program, a point to be noticed that we have defined an array as <strong>Integer</strong> . Because the reverseOrder() method does not work for the primitive data type.</p> <p> <strong>SortArrayExample4.java</strong> </p> <pre> import java.util.Arrays; import java.util.Collections; public class SortArrayExample4 { public static void main(String[] args) { Integer [] array = {23, -9, 78, 102, 4, 0, -1, 11, 6, 110, 205}; // sorts array[] in descending order Arrays.sort(array, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(array)); } } </pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: [205, 110, 102, 78, 23, 11, 6, 4, 0, -1, -9] </pre> <p>Let's see another program that sorts array elements in alphabetical order.</p> <p> <strong>SortArrayExample5.java</strong> </p> <pre> import java.util.Arrays; import java.util.Collections; public class SortArrayExample5 { public static void main(String[] args) { String [] strarray = {'Mango', 'Apple', 'Grapes', 'Papaya', 'Pineapple', 'Banana', 'Orange'}; // sorts array[] in descending order Arrays.sort(strarray, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(strarray)); } } </pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: [Papaya, Pineapple, Orange, Mango, Grapes, Banana, Apple] </pre> <h3>Without Using the Method</h3> <h3>Using the for Loop</h3> <p>In the following example, we have initialized an integer array and perform sorting in descending order.</p> <p> <strong>SortArrayExample6.java</strong> </p> <pre> public class SortArrayExample6 { public static void main(String[] args) { int temp; //initializing an array int a[]={12,5,56,-2,32,2,-26,9,43,94,-78}; for (int i = 0; i <a.length; i++) { for (int j="i" + 1; < a.length; j++) if (a[i] a[j]) temp="a[i];" a[i]="a[j];" a[j]="temp;" } system.out.println(\'array elements in descending order:\'); accessing element of the array i="0;" - system.out.println(a[i]); pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: 94 56 43 32 12 9 5 2 -2 -26 -78 </pre> <h3>Using the User Defined Method</h3> <p> <strong>SortArrayExample7.java</strong> </p> <pre> import java.util.Scanner; public class SortArrayExample7 { public static void main(String[] args) { int n, temp; Scanner s = new Scanner(System.in); System.out.print('Enter the number of elements: '); n = s.nextInt(); int a[] = new int[n]; System.out.println('Enter the elements of the array: '); for (int i = 0; i <n; i++) { a[i]="s.nextInt();" } for (int i="0;" < n; j="i" + 1; j++) if (a[i] a[j]) temp="a[i];" a[j]="temp;" system.out.println(\'array elements in descending order:\'); n - system.out.println(a[i]); system.out.print(a[n 1]); pre> <p> <strong>Output:</strong> </p> <pre> Enter the number of elements: 7 Enter the elements of the array: 12 5 56 -2 32 2 -26 Array elements in descending order: 56 32 12 5 2 -2 -26 </pre> <h2>How to Sort Subarray</h2> <p>An array derived from the array is known as <strong>subarray</strong> . Suppose, <strong>a[]</strong> is an array having the elements [12, 90, 34, 2, 45, 3, 22, 18, 5, 78] and we want to sort array elements from 34 to 18. It will sort the subarray <strong>[34, 2, 45, 3, 22, 18]</strong> and keep the other elements as it is.</p> <p>To sort the subarray, the Arrays class provides the static method named <strong>sort()</strong> . It sorts the specified range of the array into ascending order. We can also sort the array of type <strong>long, double, float, char, byte,</strong> etc.</p> <p> <strong>Syntax:</strong> </p> <pre> public static void sort(int[] a, int fromIndex, int toIndex) </pre> <p>The method parses the following three parameters:</p> <ul> <tr><td>a:</td> An array to be sort. </tr><tr><td>fromIndex:</td> The index of the first element of the subarray. It participates in the sorting. </tr><tr><td>toIndex:</td> The index of the last element of the subarray. It does not participate in the sorting. </tr></ul> <p>If formIndex is equal to the toIndex, the range to be sorted is empty. It throws IllegalArgumentException if <strong>fomIndex is greater than toIndex</strong> . It also throws ArrayIndexOutOfBoundsException if <strong>fromIndex a.length</strong> .</p> <p>Let's sort a subarray through a Java program.</p> <p> <strong>SortSubarrayExample.java</strong> </p> <pre> import java.util.Arrays; public class SortSubarrayExample { public static void main(String[] args) { //defining an array int[] a = {12, 90, 34, 2, 45, 3, 22, 18, 5, 78}; // sorts subarray form index 2 to 7 Arrays.sort(a, 2, 7); //prints array using the for loop for (int i = 0; i <a.length; i++) { system.out.println(a[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Sorted Subarray: 12 90 2 3 22 34 45 18 5 78 </pre> <hr></a.length;></pre></n;></pre></a.length;></pre></arr.length;> Folosind metoda definită de utilizator
În exemplul următor, am definit o metodă numită sortArray() care conține logica de a sorta o matrice în ordine naturală.
SortArrayExample3.java
șirul de înlocuire java
public class SortArrayExample3 { public static void main(String[] args) { int i; //initializing an array int array[] = {12, 45, 1, -1, 0, 4, 56, 23, 89, -21, 56, 27}; System.out.print('Array elements before sorting:
'); for(i = 0; i <array.length; i++) system.out.println(array[i]); invoking user defined method sortarray(array, array.length); system.out.print(\'array elements after sorting:
\'); accessing of the sorted array for(i="0;" i <array.length; { } to sort an in ascending order private static void sortarray(int array[], int n) for (int <n; j="i;" a="array[i];" while ((j> 0) && (array[j-1] > a)) //returns true when both conditions are true { array[j] = array[j-1]; j--; } array[j] = a; } } } </array.length;> Ieșire:
Array elements before sorting: 12 45 1 -1 0 4 56 23 89 -21 56 27 Array elements after sorting: -21 -1 0 1 4 12 23 27 45 56 56 89
Sortați matricea în ordine descrescătoare
The ordine descrescatoare aranjează elementele în ordinea cea mai mare la cea mai mică. Putem efectua sortarea în următoarele moduri:
- Folosind ordine inversă() Metodă
- Fără a folosi metoda
- Folosind pentru Buclă
- Folosind Definit de utilizator Metodă
Folosind metoda reverseOrder().
Java Colecții clasă oferă ordine inversă() metoda de sortare a matricei în ordine lexicografică inversă. Este o metodă statică, așa că o putem invoca direct folosind numele clasei. Nu analizează niciun parametru. Se întoarce a comparator care impune inversul ordinii naturale (ordine ascendentă).
Înseamnă că matricea sortează elementele în ordine crescătoare folosind metoda sort(), după care metoda reverseOrder() inversează ordinea naturală și obținem matricea sortată în ordine descrescătoare.
Sintaxă:
public static Comparator reverseOrder()
Să presupunem că a[] este o matrice care trebuie sortată în ordine descrescătoare. Vom folosi metoda reverseOrder() în felul următor:
Arrays.sort(a, Collections.reverseOrder());
Să sortăm o matrice în ordine descrescătoare.
În programul următor, un punct de observat că am definit o matrice ca Întreg . Deoarece metoda reverseOrder() nu funcționează pentru tipul de date primitiv.
SortArrayExample4.java
import java.util.Arrays; import java.util.Collections; public class SortArrayExample4 { public static void main(String[] args) { Integer [] array = {23, -9, 78, 102, 4, 0, -1, 11, 6, 110, 205}; // sorts array[] in descending order Arrays.sort(array, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(array)); } } Ieșire:
Array elements in descending order: [205, 110, 102, 78, 23, 11, 6, 4, 0, -1, -9]
Să vedem un alt program care sortează elementele matricei în ordine alfabetică.
data convertită în șir
SortArrayExample5.java
import java.util.Arrays; import java.util.Collections; public class SortArrayExample5 { public static void main(String[] args) { String [] strarray = {'Mango', 'Apple', 'Grapes', 'Papaya', 'Pineapple', 'Banana', 'Orange'}; // sorts array[] in descending order Arrays.sort(strarray, Collections.reverseOrder()); System.out.println('Array elements in descending order: ' +Arrays.toString(strarray)); } } Ieșire:
Array elements in descending order: [Papaya, Pineapple, Orange, Mango, Grapes, Banana, Apple]
Fără a folosi metoda
Folosind bucla for
În exemplul următor, am inițializat un tablou întreg și am efectuat sortarea în ordine descrescătoare.
SortArrayExample6.java
public class SortArrayExample6 { public static void main(String[] args) { int temp; //initializing an array int a[]={12,5,56,-2,32,2,-26,9,43,94,-78}; for (int i = 0; i <a.length; i++) { for (int j="i" + 1; < a.length; j++) if (a[i] a[j]) temp="a[i];" a[i]="a[j];" a[j]="temp;" } system.out.println(\'array elements in descending order:\'); accessing element of the array i="0;" - system.out.println(a[i]); pre> <p> <strong>Output:</strong> </p> <pre> Array elements in descending order: 94 56 43 32 12 9 5 2 -2 -26 -78 </pre> <h3>Using the User Defined Method</h3> <p> <strong>SortArrayExample7.java</strong> </p> <pre> import java.util.Scanner; public class SortArrayExample7 { public static void main(String[] args) { int n, temp; Scanner s = new Scanner(System.in); System.out.print('Enter the number of elements: '); n = s.nextInt(); int a[] = new int[n]; System.out.println('Enter the elements of the array: '); for (int i = 0; i <n; i++) { a[i]="s.nextInt();" } for (int i="0;" < n; j="i" + 1; j++) if (a[i] a[j]) temp="a[i];" a[j]="temp;" system.out.println(\'array elements in descending order:\'); n - system.out.println(a[i]); system.out.print(a[n 1]); pre> <p> <strong>Output:</strong> </p> <pre> Enter the number of elements: 7 Enter the elements of the array: 12 5 56 -2 32 2 -26 Array elements in descending order: 56 32 12 5 2 -2 -26 </pre> <h2>How to Sort Subarray</h2> <p>An array derived from the array is known as <strong>subarray</strong> . Suppose, <strong>a[]</strong> is an array having the elements [12, 90, 34, 2, 45, 3, 22, 18, 5, 78] and we want to sort array elements from 34 to 18. It will sort the subarray <strong>[34, 2, 45, 3, 22, 18]</strong> and keep the other elements as it is.</p> <p>To sort the subarray, the Arrays class provides the static method named <strong>sort()</strong> . It sorts the specified range of the array into ascending order. We can also sort the array of type <strong>long, double, float, char, byte,</strong> etc.</p> <p> <strong>Syntax:</strong> </p> <pre> public static void sort(int[] a, int fromIndex, int toIndex) </pre> <p>The method parses the following three parameters:</p> <ul> <tr><td>a:</td> An array to be sort. </tr><tr><td>fromIndex:</td> The index of the first element of the subarray. It participates in the sorting. </tr><tr><td>toIndex:</td> The index of the last element of the subarray. It does not participate in the sorting. </tr></ul> <p>If formIndex is equal to the toIndex, the range to be sorted is empty. It throws IllegalArgumentException if <strong>fomIndex is greater than toIndex</strong> . It also throws ArrayIndexOutOfBoundsException if <strong>fromIndex a.length</strong> .</p> <p>Let's sort a subarray through a Java program.</p> <p> <strong>SortSubarrayExample.java</strong> </p> <pre> import java.util.Arrays; public class SortSubarrayExample { public static void main(String[] args) { //defining an array int[] a = {12, 90, 34, 2, 45, 3, 22, 18, 5, 78}; // sorts subarray form index 2 to 7 Arrays.sort(a, 2, 7); //prints array using the for loop for (int i = 0; i <a.length; i++) { system.out.println(a[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Sorted Subarray: 12 90 2 3 22 34 45 18 5 78 </pre> <hr></a.length;></pre></n;></pre></a.length;> Folosind metoda definită de utilizator
SortArrayExample7.java
import java.util.Scanner; public class SortArrayExample7 { public static void main(String[] args) { int n, temp; Scanner s = new Scanner(System.in); System.out.print('Enter the number of elements: '); n = s.nextInt(); int a[] = new int[n]; System.out.println('Enter the elements of the array: '); for (int i = 0; i <n; i++) { a[i]="s.nextInt();" } for (int i="0;" < n; j="i" + 1; j++) if (a[i] a[j]) temp="a[i];" a[j]="temp;" system.out.println(\'array elements in descending order:\'); n - system.out.println(a[i]); system.out.print(a[n 1]); pre> <p> <strong>Output:</strong> </p> <pre> Enter the number of elements: 7 Enter the elements of the array: 12 5 56 -2 32 2 -26 Array elements in descending order: 56 32 12 5 2 -2 -26 </pre> <h2>How to Sort Subarray</h2> <p>An array derived from the array is known as <strong>subarray</strong> . Suppose, <strong>a[]</strong> is an array having the elements [12, 90, 34, 2, 45, 3, 22, 18, 5, 78] and we want to sort array elements from 34 to 18. It will sort the subarray <strong>[34, 2, 45, 3, 22, 18]</strong> and keep the other elements as it is.</p> <p>To sort the subarray, the Arrays class provides the static method named <strong>sort()</strong> . It sorts the specified range of the array into ascending order. We can also sort the array of type <strong>long, double, float, char, byte,</strong> etc.</p> <p> <strong>Syntax:</strong> </p> <pre> public static void sort(int[] a, int fromIndex, int toIndex) </pre> <p>The method parses the following three parameters:</p> <ul> <tr><td>a:</td> An array to be sort. </tr><tr><td>fromIndex:</td> The index of the first element of the subarray. It participates in the sorting. </tr><tr><td>toIndex:</td> The index of the last element of the subarray. It does not participate in the sorting. </tr></ul> <p>If formIndex is equal to the toIndex, the range to be sorted is empty. It throws IllegalArgumentException if <strong>fomIndex is greater than toIndex</strong> . It also throws ArrayIndexOutOfBoundsException if <strong>fromIndex a.length</strong> .</p> <p>Let's sort a subarray through a Java program.</p> <p> <strong>SortSubarrayExample.java</strong> </p> <pre> import java.util.Arrays; public class SortSubarrayExample { public static void main(String[] args) { //defining an array int[] a = {12, 90, 34, 2, 45, 3, 22, 18, 5, 78}; // sorts subarray form index 2 to 7 Arrays.sort(a, 2, 7); //prints array using the for loop for (int i = 0; i <a.length; i++) { system.out.println(a[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Sorted Subarray: 12 90 2 3 22 34 45 18 5 78 </pre> <hr></a.length;></pre></n;> Cum să sortați Subarray
O matrice derivată din matrice este cunoscută ca subbaraj . Presupune, A[] este o matrice care are elementele [12, 90, 34, 2, 45, 3, 22, 18, 5, 78] și dorim să sortăm elementele matricei de la 34 la 18. Va sorta submatricea [34, 2, 45, 3, 22, 18] și păstrați celelalte elemente așa cum sunt.
Pentru a sorta subbarra, clasa Arrays oferă metoda statică numită fel() . Sortează intervalul specificat al matricei în ordine crescătoare. De asemenea, putem sorta matricea de tip lung, dublu, float, char, octet, etc.
Sintaxă:
scan.nextstring java
public static void sort(int[] a, int fromIndex, int toIndex)
Metoda analizează următorii trei parametri:
Dacă formIndex este egal cu toIndex, intervalul de sortat este gol. Aruncă IllegalArgumentException dacă fomIndex este mai mare decât toIndex . De asemenea, aruncă ArrayIndexOutOfBoundsException dacă dinIndex a.lungime .
Să sortăm un subbary printr-un program Java.
SortSubarrayExample.java
import java.util.Arrays; public class SortSubarrayExample { public static void main(String[] args) { //defining an array int[] a = {12, 90, 34, 2, 45, 3, 22, 18, 5, 78}; // sorts subarray form index 2 to 7 Arrays.sort(a, 2, 7); //prints array using the for loop for (int i = 0; i <a.length; i++) { system.out.println(a[i]); } < pre> <p> <strong>Output:</strong> </p> <pre> Sorted Subarray: 12 90 2 3 22 34 45 18 5 78 </pre> <hr></a.length;>